Question

Solve 3 sin(x/2) - 1 = 0 at interval (0, 2pi)

Answer 1

\[3 \sin\left(\frac{x}{2} \right) - 1 = 0\]\[3 \sin\left(\frac{x}{2} \right) = 1\]\[\sin\left(\frac{x}{2} \right) = \frac{1}{3}\]

Answer 2

\[\frac{x}{2} = \sin^{-1} \left(\frac{1}{3} \right)\]\[x = 2 \sin^{-1} \left(\frac{1}{3} \right)\]

Answer 3

Did I clear everything?

Answer 4

Yes, thank you
but now I havae a cot question

Answer 5

2 cot^2 x - cot x = 3

Answer 6

interval (0, 2pi)