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Mathematics 12 Online
OpenStudy (anonymous):

This series converges to .........\[\sum_{n=1}^{\infty}(-\frac{ 1 }{ 2 })^{n-1}\sin^{n}(x)\]

OpenStudy (anonymous):

\[= sinx( 1 - sinx/2 + (-sinx/2)^2 + (-sinx/2)^3 ...............)\]

OpenStudy (anonymous):

Try using formula for an infitnite GP with common ratio -sinx/2 from here :)

OpenStudy (anonymous):

You'll get te answer :D

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