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prove to me sum of (n!)/(n)^(n) converge or diverge
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\[f(n)=\frac{n!}{n^n}\]lets find some values \[f(1)=\frac{1!}{1^1}=1\] \[f(2)=\frac{2!}{2^2}=2/4=1/2=0.5\] \[f(3)=\frac{3!}{3^3}=6/27=\dot2\] \[f(4)=\frac{4!}{4^4}=12/256=0.046875\] \[f(10)=\frac{10!}{10^{10}}=3628800/10000000000\approx0.000363\], as the input increases the output decreases
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