Question

The following system is solved by substitution. Which expression is substituted for z in the second and third equations?

x + 5y – z = 6
3x – y – 2z = 4
3x – 2y + 3z = 13

x + 5y + 6

x + 5y – 6

–x – 5y + 6

–x – 5y – 6

Answer 1

@evergirl Can you clarify more please?

Answer 2

that's all my paper said srry

Answer 3

ok let me try

Answer 4

–x – 4y – 10

Using equation one, we get this when we express z in terms of the other variables and the constant:

x + 4y + z = –10
z = –x – 4y – 10

–x – 4y – 10 is the expression for z that will be plugged into the second and third equations.
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Answer 5

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Answer 6

oh no .......virus?? :O

Answer 7

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Answer 8

no

Answer 9

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