Question

(logx)^3=log(x^3) please explain!! thank youuu!!

Answer 1

i made logx=a sooooooo a^3-3a=0? a(a^2-3)=0
a=0 sooo x=1
a=±sqrt 3? is it right that i do ±?
soooo it's 10^±sqrt 3 also? is there a way to simplify this further?

Answer 2

@hartnn ? :D anyone?? :D

Answer 3

10^(-sqrt3) = 1/ (10^(sqrt 3))
that the only thing i can think of.....

Answer 4

and yes, x=1,10^±sqrt 3 is correct

Answer 5

and yes it is right to do +/-

Answer 6

yay okay thank youuu!!!:)

Answer 7

welcome ^_^