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Mathematics 21 Online
OpenStudy (anonymous):

how did this expansion become like this?

OpenStudy (anonymous):

OpenStudy (shubhamsrg):

which line you didnt get ?

OpenStudy (anonymous):

the first one in the solutioin how did they simplify the term within bracket?

OpenStudy (shubhamsrg):

1+x+x^2 + x^3 = (1+x) + x^2( 1+x) = (1+x)(1+x^2) was i able to clarify ?

OpenStudy (anonymous):

omg....thank u! i was confused with synthetic division.........one more help...

OpenStudy (anonymous):

is synthetic division(trial and error ) applicable only for equations? like x^3+x^2+x+1=0?

OpenStudy (shubhamsrg):

didnt get your query ? come again ?

OpenStudy (anonymous):

in general are we allowed to equate the expression to 0 in order to find its factors?

OpenStudy (anonymous):

if u see here there is no rhs cani equate it to 0 (not for this one) in general some complicated expression

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