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Factor 6x^9-30x^7
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First, factor out the 6x^7. You'll then have (6)(x^7)(x^2 - 5). All you have left is last factor to do.
so i facroture it into a polynomial
factor
You can either leave it the way I have it or factor out hte last factor which has an x^2 in it. The last roots would be irrational but real.
so it would be 2x^7 and divided the whole numbers by that?
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I don't understand your last question.
i dont understand how the final answer will come out.
All you have left is to factor (x^2 - 5). Here, x is +-sqrt(5) because it takes the form of (x - sqrt[5])(x + sqrt[5])
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