Question

Solve \[\sqrt{3x+1}\] = x-1

Answer 1

\(\Large \sqrt{3x+1}=(x-1) \) square both sides
\(\Large (\sqrt{3x+1})^2=(x-1)^2 \)
\(\Large 3x+1=x^2-2x+1 \)

can you solve this quadratic from here?

Answer 2

and especially with radical equations, always check your solution(s) for extraneous solutions.

Answer 3

Thanks, figured it out. :)