Question

Find the equation of the tangent plane to the surface z=e^(-4x/17)ln(2y) at the point (-3,2,2,808).

Answer 1

2.808 ....?

Answer 2

???

Answer 3

(-3,2,2.808)

Answer 4

thats the point where we are taking the tangent plane at

Answer 5

you wrote (-3,2,2,808)

take the gradient, sub.s in (-3,2,2.808), that's your normal vector.
use the same points in the equation A(x-xo) +B(y-yo) ...