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Mathematics 17 Online
OpenStudy (anonymous):

Check my answers and help on #10 & #13

OpenStudy (anonymous):

hartnn (hartnn):

what answers u got ?

OpenStudy (anonymous):

for #10 try \((x-3)(x+2)=0\) and solve for \(x\)

OpenStudy (anonymous):

It's on the sheet but here: 10. ? 11. 4 times 12. f(-x)=f(x) 13. ? 14. End Behavior = neg. infinity, neg. infinity 15. (on sheet) 16. x=3 cubic; x=-3 quadratic; x=2 linear

hartnn (hartnn):

11. seems incorrect

OpenStudy (anonymous):

@satellite73 So 10 is x=3 and x=-2, right?

OpenStudy (anonymous):

@hartnn 3?

hartnn (hartnn):

when u put M(x) =0, how many values of x do u get ?

OpenStudy (anonymous):

2

hartnn (hartnn):

then it will cut x-axis 2 times .

OpenStudy (anonymous):

Ok, thanks. Is everything else correct?

hartnn (hartnn):

rest all seems fine....u need help with 10 and 13 ?

OpenStudy (anonymous):

I got 10, just 13 now

hartnn (hartnn):

\(\text{ Equation of degree n---->n zeros }\)

OpenStudy (anonymous):

I'm still confused :3

hartnn (hartnn):

if there are n zeros, then the degree of eqution must be n

OpenStudy (anonymous):

\[x ^{2}?\]

hartnn (hartnn):

the lowest possible degree is asked, which will be 2

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