How would you solve 3 (2z + 1) = 35? I got down to 6z = 32 but that wouldn't divide equally...
thats right. so z will be 32/6 only
You're going to get a fraction for an answer (which is perfectly legal)
also, remember to reduce fully 32/6 = 16/3
oh okay! well thank you!
Do any of you know how I could solve 5/3 ( 15-6) - (6-20)?
the variables are missing and so is the equals sign
so what does that mean?
means u can't solve that...if thats question is correct, then u can simplify to get a value.
you can't solve since it's not an equation (where the variables are missing)
did you mean simplify? or evaluate?
oh okay, maybe that's what threw me off
if you want to simplify or evaluate, then 5/3 ( 15-6) - (6-20) 5/3 ( 15)+5/3(-6) - 6+20 75/3-30/3 - 6+20 25-10 - 6+20 29 ------------------------------------------------------- This means that 5/3 ( 15-6) - (6-20) simplifies to 29
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