How would you solve 3 (2z + 1) = 35? I got down to 6z = 32 but that wouldn't divide equally...
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hartnn (hartnn):
thats right.
so z will be 32/6 only
jimthompson5910 (jim_thompson5910):
You're going to get a fraction for an answer (which is perfectly legal)
jimthompson5910 (jim_thompson5910):
also, remember to reduce fully
32/6 = 16/3
OpenStudy (anonymous):
oh okay! well thank you!
OpenStudy (anonymous):
Do any of you know how I could solve 5/3 ( 15-6) - (6-20)?
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jimthompson5910 (jim_thompson5910):
the variables are missing and so is the equals sign
OpenStudy (anonymous):
so what does that mean?
hartnn (hartnn):
means u can't solve that...if thats question is correct, then u can simplify to get a value.
jimthompson5910 (jim_thompson5910):
you can't solve since it's not an equation (where the variables are missing)
jimthompson5910 (jim_thompson5910):
did you mean simplify? or evaluate?
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OpenStudy (anonymous):
oh okay, maybe that's what threw me off
jimthompson5910 (jim_thompson5910):
if you want to simplify or evaluate, then
5/3 ( 15-6) - (6-20)
5/3 ( 15)+5/3(-6) - 6+20
75/3-30/3 - 6+20
25-10 - 6+20
29
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This means that
5/3 ( 15-6) - (6-20)
simplifies to
29