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OpenStudy (anonymous):
A 6.5×10^(−2) arrow hits the target at 25m/s and penetrates 3.8cm before stopping. What average force did the target exert on the arrow? 2 sig figs please
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OpenStudy (anonymous):
find acceleration from 25^2 = 2*a*.038 F*delta t = m*delta V F= m *delta V / delta t = m*a
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