a total of 13 cheetahs and rhinoceroses lived in a park. if twice the number of cheetahs exceeded three fourths the number of rhinoceroses by four, how many of each animal lived in the park?

Question

anonymous · Answer

let the cheetahs be 'x' and rhinos be 'y'
given
x + y = 13
also given 
2x = 3/4*y + 4
now you can find the answers. cant you?

anonymous · Answer

would you multiply by 2 to get x alone?

anonymous · Answer

or divide

anonymous · Answer

you need to divide the second equation by x
or better solution can be taken as
find x or y from the first equation and put the value of x or y in second ;)

anonymous · Answer

you get it?