Question

find a so that the point (-1, 2) is on the graph of f(x)=ax^2+5

Answer 1

since (-1,2) is on the graph f(x)=ax^2+5
you can put f(x)=2, and x=-1
what u get ?

Answer 2

2=a(-1)+5

Answer 3

2=a(-1)^2+5
find a from here

Answer 4

don't miss ^2

Answer 5

a = ..

Answer 6

... ?

Answer 7

3

Answer 8

?

Answer 9

very close,but not correct
2=a+5
a=?

Answer 10

-3

Answer 11

that is correct value of a

Answer 12

thank you again
i also have a question just like the one we did a question ago. do you have time?

Answer 13

few minutes only...

Answer 14

4x^2 + 25y^2 = 100

Answer 15

intercepts?

Answer 16

yes there will be four
i know.

Answer 17

25,0 -25,0 for x?

Answer 18

nopes

Answer 19

y 0 -4 0 4

Answer 20

nopes

Answer 21

darn.. can u help?

Answer 22

u got x^2 =25 right ?

Answer 23

yes

Answer 24

5

Answer 25

-5

Answer 26

those will be x ints? (-5,0) (5,0)

Answer 27

\(\checkmark\)

Answer 28

0,-2 0,2

Answer 29

y

Answer 30

that is also \(\checkmark\)

Answer 31

thank u so much. when r u on next? u should be my reg helper.

Answer 32

idk, i come online when i m free...

Answer 33

oh ok.