98x + 133y = 427

Specify particular the answers (x,y) where x0 and y0

I get the answer (-244,183) or the general answer x= 19n-244 y= 183-14n

I don't really get the x0, y0 part, could anyone guide me through it?

Question

98x + 133y = 427

Specify particular the answers (x,y) where x>0 and y>0

I get the answer (-244,183) or the general answer x= 19n-244   y= 183-14n

I don't really get the x>0, y>0 part, could anyone guide me through it?

anonymous · Answer

they want u to find n's for which x and y are positive so u need to solve this inequalities
$$19n-244>0$$$$183-14n>0$$

anonymous · Answer

So the answer should just be where $$n >\frac{ 244 }{ 19 }$$
or
$$n <\frac{ 183 }{ 14 }$$

Right?

anonymous · Answer

not or ... it is and...

anonymous · Answer

thats right ...just note that they are simultaneous

anonymous · Answer

So the answer lies within the interval $$\frac{ 244 }{ 19}< n < \frac{ 183 }{14}$$ ?

anonymous · Answer

exactly

anonymous · Answer

just one number satisfies that inequalities :)

anonymous · Answer

13, thanks alot for your help! :D

anonymous · Answer

no problem