Question

find the maximum and minimum value of y=3x^3 - 4x +2

Answer 1

\[\frac{ d (3x^3 - 4x +2)}{ dx} = 9x^2-4\]

Answer 2

9x^2-4=0

x= 2/3

x=-2/3

nw wat to do

Answer 3

as in the range of the function? its a cubic; odd integer degrees rise towards infinity and dive towards negative infinity

Answer 4

if your trying to determine the bumps and dips; take the derivative a second time, insert the zeros from that, and see if the signs are positive or negative

Answer 5

positive opens up; U which translates as a min

negative opens Down n, which translates as a max