Question

hi! where did i get wrong?
1-logbase4 x= -logbase8 x

answer is supposed to be x=64?

what i did... i made it 1=logbase4 x-logbase8 x
then i changed the base thing... so i used log base 2
so i had...
logbase2 x over 2 (from logbase2 4) - logbase2x over 3 (from logbase2 8)
i factored out logbase2x so i had
logbase2x (1/2-1/3)
then i made it exponential so x/6=2 so i got 12????

Answer 1

@hartnn please? :D

Answer 2

how did u change the base ?

Answer 3

\(\huge \log_b a = \frac{log a}{log b}\)

Answer 4

oh wait you are correct till
logbase2x (1/2-1/3)=1
so
(1/6) log_2 x = 1
log_2 x =6
x= 2^6 = 64

Answer 5

got the error ?

Answer 6

@dydlf

Answer 7

sorry for the late reply! anyway OHHHHHH i get it!! YES YES YES! thank youuu!!!

Answer 8

welcome ^_^