Question

Find the number of real solutions for the equation
3x^2_6x+3=0

Answer 1

3x^2-6x+3=0 ?

Answer 2

whoops +3

Answer 3

3x+6x+3=0

Answer 4

ax^2+bx+c = 0
\[\Delta=b^2-4ac\]
if \[\Delta = 0\] then one real root
if \[\Delta > 0\] two real roots
if \[\Delta < 0\] no real roots

Answer 5

this is called discriminant

Answer 6

so there is none?

Answer 7

or two?

Answer 8

3x^2+6x+3=0 this is the equation ?

Answer 9

3x+6x+3=0

Answer 10

no square ?

Answer 11

so what i said isnt relevant

Answer 12

9x + 3 =0
9x = -3
x = -3/9
one solution here

Answer 13

but are you sure there is no x^2 ?!

Answer 14

positive thanks.