Question

Tough derivative problem involving inverse trig.

Answer 1

\[\arccos(\frac{ b+acosx }{ a+bcosx })\]

Answer 2

\[0 \le x \le \pi , and , a>b>0\]

Answer 3

\[-\frac{ 1 }{ \sqrt{1-(\frac{ b+acosx }{ a+bcosx })^2} }\]

Answer 4

hello

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