Ask your own question, for FREE!
Mathematics 18 Online
OpenStudy (anonymous):

Evaluate the summation 1/1^2 + 1/2^2 + 1/3^2 +...+ 1/n^2; n = 1

OpenStudy (anonymous):

for n=1 u just need one term\[\frac{1}{1^2}\]

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!