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If sec x = 3/2, what is the value of y? a) 3/4 b) 4/3 c) 1/3 d) 9/4
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\[secx = \frac{ 1}{ cosx}\] so :\[\frac{ 3 }{ 2} = \frac{ 1 }{ cosx} => cosx = 2/3\] now : \[\frac{ 2 }{ 3 } = \frac{ 2 }{ 9y } => 9y = 3 => y =1/3\]
ohhh thankyou sooooo much(:
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