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write the equation of the line that passes through (4,3) and is parrallel to the line y=x+1
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Since the line has to be parallel to y=x+1, it has to have the same slope, so when you set it up the equation will start like this:\[Y=x+b\]Since y is given as 3 and x equals 4, you know that 3=4+b. Solve for b and you get b=-1
okay so how would you write it at the end
as an equation
y=x-1
thanks can we do another?
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