Question

Find the value of k so that the graph of y=(x+5)^2+k passes through the point (0,−12).

Answer 1

so x=0 and y=-12

Answer 2

Just substitute in (0,-12) into the equation... and then solve for k

y = (x + 5)^2 + k
-12 = (0 + 5)^2 + k
-12 = 5^2 + k

Solve for k...

Answer 3

-12=(0+5)^2+k
-12=25+k
k=-25-12=- 37

Answer 4

@1193ped ok

Answer 5

thanks man