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2x^2-4x=1 Pleasse help!
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do you know the quadratic formula?
X=-,+ square root of 3/2+1
write that as 2x^2-4x-1=0 Compare this quadratic equation with \(ax^2+bx+c=0\) find a,b,c then the two roots of x are: \(\huge{x=\frac{-b \pm \sqrt{b^2-4ac}}{2a}}\)
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