Question

Solve by completing the square:
3x^2-x-4=0
the answer i got was x= 1/6 +or- radical 17/12
can someone please check if its right ? thank you!

Answer 1

You can use the quadratic equation [ (-b± √(b^2-4ac))/2a ]
1± √(1^2-4(3)(-4) / 2(3)
1± √(49) /6
(1 ± 7)/6
-6/6 , 8/6
-1, 4/3