Question

Solve each system using substitution. Check your solution.

h=6g-4
h=-2g+28

Answer 1

2.h= 6g-4...(i)
h= -2g+28...(ii)
6g-4=-2g+28
+2g +2g
8g-4=28
8g=32
g=32/8
if you not - sign
solve for h
h=6g-4

Answer 2

g=4.

Answer 3

right

Answer 4

so how do I solve for h?

Answer 5

im not sure.. thats the only part i no;) sry..

Answer 6

alright. thanks anyway =)

Answer 7

np=D

Answer 8

medal me?;)

Answer 9

i fanned you. i want to give medal to person who solves all 3 parts of the problem. only fair that way. i appreciate your help though. :D

Answer 10

since you know g now, plug it into one of the original equations and solve for h

Answer 11

h=6(4)-4
h=20

Answer 12

To check your solutions, plug both of your answers into one of the original equations and if its true, you were right

20=6(4)-4
20=20

So the answers are right.
h=20
g=4

Answer 13

well yeah, i know i could just plug it in, but my teacher taught me another way. i had to replace and all this other stuff. do you know that way?

Answer 14

Well to solve for h that way, do the same thing you did for g.

Answer 15

the first thing i did to solve for g was 6g-4=-2g+28

how do i do that to solve for h?

Answer 16

First solve one of the equations for g.
h=6g-4
h+4=6g
(h+4)/6=g

now replace g in your other equation with (h+4)/6
h=-2((h+4)/6)+28

and solve for h.

Answer 17

h=20. ok. well i was looking through my notes because the other way that i had asked for you to help me with was unfamiliar with me. so many numbers. i just found out that the first way you had showed me was the way our teacher would have solved the problem. im sorry i made you wait so long and that i made you write all this stuff. Thanks for all your help. I understand what to do now.

Answer 18

You're welcome.