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Melinda has nickels and quarters in her bank. She has four fewer nickels than quarters. She has $3.70 in the bank. How many coins of each does she have?
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To solve this you need to set up a system of equations. In this case these would be your two equations: n+4=q .25q+.05n=3.70 Now you should be able to solve from here!
I thought it would be 4-Q=N since there are four fewer nickels than quarters
http://www.algebra.com/algebra/homework/word/coins/Word_Problems_With_Coins.faq.question.624537.html
^make sure to replace the numbers with the correct cents.
Shamuta, I don't think that's correct. She has four fewer nickels than quarters. Therefore she has four more quarters than nickels so it's either q-4=n or n+4=q
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