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For what values of x in [0,2π] does the graph of f(x)=x+2sinx have a horizontal tangent? List the values of x below.
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I don't know how to set up the equation, that's what I was asking.
Find the first derivative, f'(x) Solve f'(x)=0 (horizontal tangent occur when the slope is zero). You can find x from here.
f'(x)=1+2Cos(x) 1+2Cos(x)=0 \(Cos(x)=\large\frac{-1} {2} \) \(Cos^{-1} \large(\frac{-1} {2})=x\) x=120 and 300
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I skipped out some steps but I am assuming you are familiar with trig
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@Kalen Are u there?
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