Question

10^log(x^2 + x) = 2

Answer 1

if the log is base ten, then \(10^{\log(x^2+2)}=x^2+2\)

Answer 2

10^log(x^2+x)=2
taking log on both sides
log(x^2+x).log10=log2
log(x^2+x).1-log2=0
log((x^2+x)/2)=0
(x^2+x)/2=10^0
(x^2+x)/2=1
x^2+x=2
x^2+x-2=0
x^2+2x-x-2=0
x(x+2)-1(x+2)=0
(x-1)(x+2)=0
x-1=0 or x+2=0
x=1 or x=-2

Answer 3

10^log(x^2 + x) = 2,,as satellite said if the log is base 10 then
(x^2 + x) = 2 so that
x^2 + x - 2 =0 factoring
(x+2)(x-1)=0
x=-2 and x=1 ans