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Mathematics 20 Online
OpenStudy (anonymous):

factor 5(x2+1)∗5x(25x−2)3+2(25x−2)2∗25(x2+1)

OpenStudy (anonymous):

just distribute

hartnn (hartnn):

or you can factor out (x^2+1)(25x-2) from both terms

OpenStudy (anonymous):

true

OpenStudy (anonymous):

for GCF

hartnn (hartnn):

huh ? where does GCF come from?

OpenStudy (anonymous):

never mind, i get it. thanks.

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