Question

Sin6θ - sin 4θ + sin2θ = ?

Answer 1

2 sin 4x .cos2x - sin 4x

Answer 2

How ?

Answer 3

sin a + sin b = 2 sin (a+b)/2 . cos (a-b)/2

Answer 4

^ Ok

Answer 5

Got this formula whats next

Answer 6

nothing xD

Answer 7

2 sin 4x .cos2x - sin 4x

sin 4x ( 2cos 2x -1)

Answer 8

u need to find general solution?

Answer 9

I dont get it really :(

Answer 10

whaat?? o.O

Answer 11

Please Explain it to Me :(

Answer 12

did u get this 2 sin 4x .cos2x - sin 4x

Answer 13

No Thats Exactly what i didnt get, where did this come from ?

Answer 14

lol using this sin a + sin b = 2 sin (a+b)/2 . cos (a-b)/2

sin 6x + sin 2x

Answer 15

3sin (2x) is the simplified form.

Answer 16

\[\sin(6x)-\sin(4x)+\sin(2x) =\sin(6x)+\sin(-4x)+\sin(2x)\]
\[=2\sin(\frac{ 6x-4x }{ 2 })\cos(\frac{ 6x-4x }{ 2 })+\sin(2x)\]
\[=2\sin(x)\cos(x)+\sin(2x)\]
\[=2\sin(2x)+\sin(2x)\]\[=3\sin (2x)\]