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2(4m − 1) + 5 ≥ 10m − 7
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2(4m-1)+5 ≥ 10m-7 8m-2+5 ≥ 10m-1 8m+3 ≥ 10m-1 Now, bring all the constants on one side and variables on the other. I will take the constants on the left side and variables on the right. then, 3+1 ≥ 10m-8m 4 ≥ 2m 2 ≥ m ,i.e., m≥2
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