Question

find f ' (x) and f '(c)
f(x)= (1/3)(2x^3 - 4)
value of c = 0

Answer 1

i'm not really sure how to get started

Answer 2

\[
f(x)=\frac13\left(2x^3-4\right)\\
f'(x)=2x^2\\
f'(0)=0.
\]

Answer 3

how did you get those primes?

Answer 4

I used both\[
f(x)=ax^{b}\Longrightarrow f'(x)=abx^{b-1},
\]and\[
f(x)=c\Longrightarrow f'(x)=0.
\]

Answer 5

ah ok, thanks