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A particle starts at the origin and moves along the curve y=(2x^(3/2))/3 in the positive x direction at a speed of 3cm/s. Find the position of particle at time t=6. Im not sure how to approach this. I feel like at time t=6 the particle has moved 18cm in the x direction. Does this mean I just plug 18 into to formula or do I need to do something involving arc length?
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this question came up earlier today, let me see if I can find it...
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