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Mathematics 12 Online
OpenStudy (anonymous):

factor the polynomial 9c^2+6c+1

OpenStudy (anonymous):

= 9c^2 + 3c + 3c +1 = 3c(3c+1) +1(3c+1) = (3c+1)(3c+1) (3c+1)^2

OpenStudy (anonymous):

(3c+1)^2. When you solve problems like this, multiply the first coefficient and the constant and try to find fatcors of that product whose sum is the second coefficient

OpenStudy (anonymous):

Got it now..??

OpenStudy (anonymous):

yes thanks for all your help

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