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Mathematics 9 Online
OpenStudy (anonymous):

Lef f(x) = (4x^2-6x+5)/(8x^2+1x-6) what is f'(x) at x=1?

OpenStudy (anonymous):

f'(x)= [(8x-6)(8x^2+x-6) - (4x^2-6x+5)(16x+1)]/(8x^2+x-6)^2 Then just simplify from there.

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