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Find the equation of the tangent line for the given function at x=(pi/3). f(x)=4tan(x)
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So I already worked this problem out, and found that the slope of the tangent line is 16.
I give the equation of the tangent line using y-y1=m(x-x1)
But I think I'm missing something. Is there a y1 value here? I don't see one.
x1=(pi/3), m=(16), y1=(?)
I thought that y would be zero, but wolfram is telling me that is incorrect.
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y = 4tan(pi/3)
Oh...psshh. THat makes sense lol.
I get stupid sometimes.
algebra fail lol.
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Ha, yep. Thanks.
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