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solve by factoring 49x^2 - 16 = 0
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Is this your very first ques. on here?
this = (7x-4)(7x+4) do you need anything beyond that?
yes :/
i think that should help. Thank you :)
x= 4/7, -4/7
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This is what's called a perfect square, which means there isn't a middle term. \[49x ^{2}-16=0\] (7x-4)(7x+4)=0 Now check using FOIL: First: 7x X 7x= \[49x^{2}\] Outside: 7x X 4= 28x Inside: 7x X -4= -28x Last: -4 X 4= -16 The 28x and -28x cancel each other out and you are left with \[49x ^{2}-16\]
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