How to find the indicated derivative of 6t^3+3/t^4 when all my answer choices are two fractions???

Question

anonymous · Answer

$$f(t) = 6t^{3} + \frac{3}{t^{4}} = 6t^{3} + {3}{t^{-4}}$$
Do chain rule to get f'(t)
$$f(x) = a*g(x)^{n}$$
$$f'(x) = (n-1)*a*g(x)^{n-1}*g'(x)$$

anonymous · Answer

f'(x)= 12t-12t^-5

anonymous · Answer

the derivative of 6t^3 is 3*6t^(3-1) = 18t^2

anonymous · Answer

so i got  18/t^2 - 12/t^5 ?

anonymous · Answer

18t^2 - 12/t^5
that '/' doesn't need to be in there

turingtest · Answer

your problem is$$6t^3+\frac3{t^4}$$or$$\frac{6t^3+3}{t^4}$$?

anonymous · Answer

the first one but all my answer choices are fractional like the one i posted in reply to 2Le

anonymous · Answer

they are simplifying it weird..

turingtest · Answer

very weird

anonymous · Answer

is the answer $$\frac{18t^7 -12}{t^5}$$

turingtest · Answer

the derivative is$$18t^2-\frac{12}{t^5}$$which you could write with a common denominator if you want to be stupid about it :P

turingtest · Answer

$$18t^2-\frac{12}{t^5}=\frac{18t^7-12}{t^5}$$is that a choice?

anonymous · Answer

no, the choices look like: -6/t - 12/t^5

and 4 others in similar format and signs are all the same but some powers vary and some numerators

turingtest · Answer

well the -12/t^5 part is fine, but something is screwy with the first term

anonymous · Answer

oh sorry, it actually looks like the second one -_- haha. (your first post)

turingtest · Answer

sweet :)

anonymous · Answer

everything under t^4...

anonymous · Answer

those solution manuals and answers in the back are usually written by some sort of computer. Check your work and reformatting it is usually a second part of the problem.

anonymous · Answer

it is a computerized old quiz i am reviewing for a test and its the only one im stumped about