Question

Anyone know how to solve this differential equation?
sin(x+y)dy=dx

Answer 1

How do I solve this differential equation?

Answer 2

v=x+y
v'=1+y'
y'-cosec(x+y)=0
v'-1-cosecv=0
v'=1+cosecv
dv/(1+cosecv)=dx

Answer 3

sinv/(1+sinv)*dv=dx take integral

Answer 4

Ok, let me chew on this for a bit... thanks!

Answer 5

np..

Answer 6

so... 1/(1+cosec v) = sin v / (1 + sin v) ?

Answer 7

is this an identity that I should know?

Answer 8

cosecx=1/sinx