Question

How do you evaluate the integral using the substitution method? 6.4e^(-3x+6)

Answer 1

substitute u = -3x+6

Answer 2

is that 6*4 or 6.40 ?
\[\int\limits_{}^{} 64^{-3x+6} dx = -1/3\int\limits 64e^{u} * du = (64/3)*e^{-3x+6}\]

Answer 3

...+C

Answer 4

u get it, make u the subst. then differentiate it, chug it into dx and voila! vraiment!