Question

y varies directly as the square of x. When x = 2, y = 20. Find y when x = 4.

Answer 1

y= x^2+16
now as x= 2 then y=2^2 +16 = 20
as x=4 then y= 4^2 +16 = 32

Answer 2

well done!

Answer 3

thanks!

Answer 4

welcome