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Find an equation for the line through the origin that is perpendicular to the line ax + by = c. Perpendicular slopes = Opposite reciprocals
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by=-ax+c -> y=(-a/b)x+c/b so it will be y=(b/a)x+d -> ay-bx=d
What is the slope of the line ax + by = c also?
-a/b
-bx + ay = c put x,y = 0,0 ... c=0
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