A force F= 13Ni +13Nj acts on the hockey puck. Determine the work done if the force results in the puck's displacement by 4.2m in the +x direction and the 25m in the -y direction.

Question

anonymous · Answer

Apply W=Fd to each force separately:  multiply the i component of the force by the x distance, then multiply the j component of the force by the y distance.  Include the negative - the negative means that the puck is losing energy due to that force but gaining energy due to the X force.  Use normal (scalar addition) to add the two parts together for the total work.