Question

Y varies directly as the square of x. When x = 4, y=8 . Find x when y = 32

Answer 1

Is that exactly how the question is written?

Answer 2

If y varied as the square of x, y would equal x^2, and 4^2 does not equal 8.

Answer 3

thats what im saying and thats how it is written

Answer 4

y varies directly as the square of x
y=k(x^2)

When x=4, y=8
8=k(4^2)
Solve for k! :D Then use your new found k value, and plug in the new y coordinate, and solve for x! :)

Answer 5

@geoffb 'varies directly' means it's a constant multiple of what it's varying with, so you have to multiply by k.

Answer 6

Thank Cliff. :) I caught that as soon as I read @zepdrix's response. Definitely didn't think it through.