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solve by the quadratic formula and simplify answer: x^2-3x-1=0
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a=1 b=-3 c=-1 plug into: \[\frac{ -b \pm \sqrt{b ^{2}-4ac } }{ 2a }\]
first calcule the discriminant with formula D= sqrt(b^2 -4ac) so and after this x1 ,x2 = (-b +/- sqrt(b^2 -4ac))/2a = ... hope that you have understood it right good luck bye
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