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Solve for x. (round to 3 decimal places). e^x=5
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HINT: Add ln to both sides.
\[\large{\ln e^x = \ln 5}\]
hmmm, so would I do something like ln+e^5=ln+5?
i got answer of 1.609 is whatg should = to... Does that sound right?
Actually I mean take the natural logarithm of both sides. Sorry for confusion.
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Yup, this is correct.
x = 1.609
awesome, thank you for you help and fast responses :)
No problem.
makes sense now, lol
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