Question

Find the equation of the line passing through
(−3, 1) and perpendicular to
3y = −x + 7

Answer 1

slope of given line line is
m=-1/3
if the required line is perpendicular then slope will be m=3
use point slope form
y-y0=m(x- x0)
where m=3
(x0,y0)=(-3,1)

Answer 2

would it be y = 3x+10?

Answer 3

yes

Answer 4

thank you!

Answer 5

welcome :)