Suppose your 1140kg sports car has a 280hp engine that's 40% efficient. (That is, 40% of the 280hp can be converted into the car's motion.)

Find the car's maximum speed after accelerating from rest for 3.1s .

So far I think the formula is v= P/F but the only thing throwing me of is the percentage of efficiency. Any help would be great. Thanks!

Question

Suppose your 1140kg sports car has a 280hp engine that's 40% efficient. (That is, 40% of the 280hp can be converted into the car's motion.)

Find the car's maximum speed after accelerating from rest for 3.1s .

So far I think the formula is v= P/F but the only thing throwing me of is the percentage of efficiency. Any help would be great. Thanks!

anonymous · Answer

efficiency indicates in this case that out of maximum power (280 hp) only its 40% can be utilized..substitute the utilized power in the formula..can yo do it now?

anonymous · Answer

OMG!! That simple... lol WOW. Ok, thanks.