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The gas piston of an M4 carbine rifle with in initial position of x0=5[mm].experiences a velocity defined by x’=3+5t for one second. What is the piston’s finale position?
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plz solve it in details ...thanks
\[ {dx \over dt} = 3 + 5t \\ \int dx = \int( 3 + 5t) dt = x = 5t^2/2 + 3t + c \\ put, x=0, when \;t = 0 \\ that \; would \; give \; c =5, \\ now \; put \; t=1 \] in 5t^2/2 + 3t + 5 and get your answer.
wat is t^2 ???
\[ {5t^2 \over 2} + 3t + 5 \]
yea tanx aloooooooooooooooooooooot it's 10.5 mm
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